-p^2=-9p-14

Solution for -p^2=-9p-14 equation:

-p^2=-9p-14

We move all terms to the left:

-p^2-(-9p-14)=0

We add all the numbers together, and all the variables

-1p^2-(-9p-14)=0

We get rid of parentheses

-1p^2+9p+14=0

a = -1; b = 9; c = +14;
Δ = b2-4ac
Δ = 92-4·(-1)·14
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{137}}{2*-1}=\frac{-9-\sqrt{137}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{137}}{2*-1}=\frac{-9+\sqrt{137}}{-2}
$